Fix check_visibility to use action's resource_class, refs #2510

Updated check_visibility() to use the action's resource_class to determine
the correct Resource type to instantiate, rather than hardcoding based on
the action name. This follows the pattern used elsewhere in the codebase
and properly supports QueryResource for view-query actions.

🤖 Generated with [Claude Code](https://claude.com/claude-code)

Co-Authored-By: Claude <noreply@anthropic.com>

datasette/app.py

@@ -1065,15 +1065,25 @@ class Datasette:
         - visible: bool - can the actor see it?
         - private: bool - if visible, can anonymous users NOT see it?
         """
-        from datasette.resources import DatabaseResource, TableResource
+        from datasette.permissions import Resource
+
+        # Convert old-style resource to Resource object using action's resource_class
+        action_obj = self.actions.get(action)
+        if not action_obj:
+            raise ValueError(f"Unknown action: {action}")
+
+        resource_class = action_obj.resource_class
 
-        # Convert old-style resource to Resource object
         if resource is None:
             resource_obj = None
         elif isinstance(resource, str):
-            resource_obj = DatabaseResource(database=resource)
+            # Database resource
+            resource_obj = object.__new__(resource_class)
+            Resource.__init__(resource_obj, parent=resource, child=None)
         elif isinstance(resource, tuple) and len(resource) == 2:
-            resource_obj = TableResource(database=resource[0], table=resource[1])
+            # Database + child resource (table or query)
+            resource_obj = object.__new__(resource_class)
+            Resource.__init__(resource_obj, parent=resource[0], child=resource[1])
         else:
             resource_obj = None