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If only one distinct value, record that in most_commond and leave least_common as null
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@ -1961,7 +1961,6 @@ class Table(Queryable):
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"select [{}] from [{}] limit 1".format(column, table)
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"select [{}] from [{}] limit 1".format(column, table)
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).fetchone()[0]
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).fetchone()[0]
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most_common = [value]
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most_common = [value]
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least_common = [value]
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else:
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else:
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most_common = [
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most_common = [
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(r[0], r[1])
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(r[0], r[1])
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